গণিতজ্ঞ
#compititiveexam #maths #jeemainmarksvspercentile #mathproblem #jeemainmath
0:41
গণিতজ্ঞ
#compititiveexam #maths #mathproblem #jeemainmath #mathstricks #jeemainmarksvspercentile
0:28
গণিতজ্ঞ
#compititiveexam #maths #jeeadavanced #mathproblem #jeemains #mathstricks
0:58
গণিতজ্ঞ
#compititiveexam #maths #jeeadavanced #mathproblem #jeemains #mathstricks
0:51
গণিতজ্ঞ
#compititiveexam #maths #jeeadavanced #mathproblem #mathstricks #jeemains
0:23
গণিতজ্ঞ
#compititiveexam #maths #jeeadavanced #mathproblem #jeemains #mathstricks
1:00
গণিতজ্ঞ
#compititiveexam #maths #jeeadavanced #mathproblem #jeemains #mathstricks #education
1:00
গণিতজ্ঞ
#compititiveexam #maths #jeeadavanced #mathproblem #jeemains #mathstricks
0:35
গণিতজ্ঞ
#compititiveexam #maths #jeeadavanced #mathproblem #jeemains
0:39
গণিতজ্ঞ
#compititiveexam #maths #jeeadavanced #mathproblem #jeemains
0:55
গণিতজ্ঞ
#compititiveexam #maths #jeeadavanced #mathproblem #jeemains
0:52
গণিতজ্ঞ
#compititiveexam #maths #jeeadavanced #mathproblem #jeemains #mathquestion
0:43
গণিতজ্ঞ
#compititiveexam #maths #mathematicsproblem #jeeadvanced #jeemains
0:31
গণিতজ্ঞ
#compititiveexam #maths #mathematicsproblem #jeeadvanced #jeemains #mathstricks #mathsolutions
0:44
গণিতজ্ঞ
#compititiveexam #maths #mathematicsproblem #jeeadavanced #jeemains #mathstricks
1:00
গণিতজ্ঞ
#compititiveexam #maths #jeeadvanced #jeemains
1:00
গণিতজ্ঞ
#compititiveexam #maths #jeeadvanced #jeemains
0:42
গণিতজ্ঞ
#compititiveexam #maths #jeemains #jeeadvanced
0:53
গণিতজ্ঞ
#compititiveexam #maths #mathematicsproblem #jeeadvanced #jeemains
0:39
গণিতজ্ঞ
#compititiveexam #maths #mathematicsproblem #mathproblem #challengingmathematicsproblems
0:49
গণিতজ্ঞ
#compititiveexam #maths #mathematicsproblem #mathproblem #education #challengingmathematicsproblems
1:00
গণিতজ্ঞ
#compititiveexam #maths #mathematicsproblem
0:58
গণিতজ্ঞ
If f(x) = √((log_3(x))²-3(log_3(x))-4) Then find the domain of x||
3:36
গণিতজ্ঞ
If α = ( cos (2π/n) + i sin (2π/n)) what is the value of 1 + α^p+α^(2p)+.....+ α^(n - 1)p ।।
4:46
গণিতজ্ঞ
#compititiveexam #maths #mathproblem #mathquestion
0:32
গণিতজ্ঞ
Simplify 1/cos θ + 1/(sec θ - tan θ) । Academic approach and Competitive approach
5:25
গণিতজ্ঞ
θ = α + β, φ = α - β and tan α = λ tan β then prove that ( λ + 1 )sin φ = ( λ - 1 )sin θ
6:20
গণিতজ্ঞ
Simplify tan A/( 1 - cot A) + cot A/( 1 - tan A)
6:36
গণিতজ্ঞ
If tan θ = k , then show that sec θ + tan³ θ. cosec θ = ( 1 + k²) ^( 3/2)।।competitive approach ।
5:00
গণিতজ্ঞ
If x²-3x+1=0 then (x⁴+1/x²)/(x²+5x+1)=?
5:20
গণিতজ্ঞ
solution of √(2+√(2+√(2+√(2......∞=?
4:28