bro the answer is b. because here f(x) =lg{(1+x)/(1-y)}[ let this be 1]that means that when input is x the expression is above but when f(y) is there means input will be y the thing will become f(y)=lg{(1+y)/(1-y)} [let this be 2] so f(x)+f(y)= lg(1)+lg(2) which by property of lg of same base will be lg(1Γ2)=lg(1+y+x+yx)/(1-x-y-xy)[let this be3] and if you put option (b) inside in f(x) or f(argument written inb only argument not f symbol)={(1+(option b)}/{(1-(optionb) you will ge same as lg[3] so
Bro its hard for an IX student
B is the answer The question needs the knowledge of 2 logarithm formulae Log(ab)=loga+logb Log(a/b)= loga-logb Use these formulas to simplify 2 log functions fx and fy Equate the argument of resultant log function to (1+z/1-z) Answer will be fz which is option b
Answer may be B,f(x+y/1+xy)
Nice question bro I really love it broπβ€β€β€β€
Bhai mene toh page le hi ans de Diya ππ Exam pass π
How can be this IX class Mathematics π
our teacher made us try this question
is my left earphone damaged??
f of x? Function of x
Ans. A, distributive property nahi kya, pardon me if I'm wrong, I am in class 7 π π
Tf the question is wrong.. there is no eqn of f(y)
You are very smart! :D I wish I can do this in 8th grade also. Do you have any advice?
My right ear ππ
Answer b bro it's so easy with time taking a bit
Hit 1 Put x=1/2,y=1/3 Optn B will come,to surely deny D put x,y=0,0
The correct option is B
IIT dholakpur confirmed
@Deniz.841