Yep. Turns a complex (pun intended) integral into simple algebra for his students. Now that's a teacher!
My favorite professor at MIT.
Fair enough, I inhabit the complex domain, being a worker with signals, and so that would more-or-less be my way of doing it, although I would probably use the (to us) well-known identity cos( x ) = cosh( ix ) = ( exp( ix ) + exp( - ix )) / 2 :- I = integral( exp( -x ) cos( x ) dx ) substituting p = -x, we have dp = -dx exp(-x) = exp(p) cos(x) = cos(-x) = cos(p) Using the easily memorable identity cos( x ) = cosh( ix ) I = - integral( exp( p ) cosh( ip ) dp ) ( definition of cosh( x )) = -integral( exp(p)(( exp( ip ) + (exp(-ip))/2 ) ( defactoring ) = -1/2 x integral(exp((1+i)p) + exp((1-i)p ) ( integrating ) = -1/2 x (exp(1+i)p)/(1+i) + exp((1-i)p)/(1-i)) ( adding fractions ) = -1/2 x exp(p) * ((1-i)exp(ip) + (1+i)exp(-ip)) / ((1+i)(1-i)) ( expand and collect complex exponentials ) = -1/2 * exp( p ) x ( 2 cos(p) + 2 sin(p) ) / 2 ) (resubstituting p = -x ) = exp(-x)/2 x ( sin( x ) - cos( x ) ) no messing around with normalization or only considering real parts ( a possible source of doubt to the inquiring young mind ) needed.
Brilliant! Fantastic, straightforward exposition....beautiful. The internet really is a game changer 4 learning
this is my second time seeing a lecture of Prof Arthur Mattuk after ten years
This is an awesome video, but you did forget the ' + c '
Man, do I miss this course. Pure gold
"This is what separates the girls from the women."
@Ghaiyst Wikipedia: Euler's formula
This guy is amazing
es una forma interesante de resolver con números imaginario porque usualmente lo resolvemos integración por partes pero una interesante clase en el prestigioso MIT saludos desde UNTELS LIMA PERU
thanks, that's definitely easier than integrating by parts!
if I had a chalkboard or dry erase board setup like that in my house, I'd have no use for video games.. only more chalk or dry erase markers lol
Damn it! it was just lovely.
diffetetial equations and partial differential equations are totally different!
Fascinating...
3:16 "Damn it.. this just always happens... well fuck it."
@Ghaiyst did you really had a loo k at Euler's formula which is exactly: e^'ix) = cos(x ) + i sin(x). N.B. the method given in the video is nowhere near the simplest way to tackle with this indefinite integral; sufices to write that a primitive function of e^(-x) cos(x) is e(-x)( Acos(x) + Bsin(x)) and allyou need to do is equal derivates of both parts to get a simple linear system with A and B as unknown quantities...(takes less than 1 minute...)
integrating by parts seems way easier
@davidr6540