H.w by taking LCM of 9:6 =18 Train A in 2 hrs - 2*2= 4 Remaining=14/5= 2hrs 48 min 11:03 AM
Thank you sir 15:35 28:04(Important) 36:00(Concept) 51:22 55:42 58:02(See the difference b/w this and previous question) 1:00:28 1:02:40(Important) 1:19:25 Let the distance 18(LCM of Time 9hr & 6hr) Speed of A = 18/9 =2 and B = 3 For relative speed 2(Speed)ร2(Time)=4 km Now dist. is 14 and time is same 14 /5(opposite direction) 14/5 which means 2 hr and 48 min so ans will be 11:03
Mind blowing ๐๐
Q. 26. Total distance lcm of 9, 6 =18 . Train A 2ร2 =4 . 18-4= 14. 14/5= 2h 48min. Meating time = 8:15 + 2h 48min = 11:03. ๐
Excellent Class ๐๐๐๐๐๐
11:03 option B is correct
Best series till date now โคโคโค most efficient way of revision
11:03 option number (B)
sir Ram- Ram this series very is helpfull for to revise the entire concept of the chapter. yesterday i revised time speed and distance from rakesh yadav classnotes but forgot some two three concept but your golden video has made all the concept doubt free as well as you have tought some new approach to grab the core of the question. i also use test ranking web sir for take test which fill me with great enthusiasm and courage
Q26 = b 11:03am lcm leke phir time equal karke relative speed concept use karke ayega
all correct โ โโ โ26 out of 26.
Q26- 11:03 min . Nice session sir
Option B ๐๐๐
b is the right answer๐
Option bbb โคโคโคโค
Option b.. Speed ka ratio 2:3 total distance 18km Remaining D 18-2*2 =14 14รท5= 2.8 i.e 2hr 48 Add 2.48+ 8.15= 11.03am
11:03โ๏ธ(Questions no 26)
thanks sir for this session โค
Hw-b... โคโคโคโค
@GaganPratapMaths