you explained one by one clearly. Thank you!
Always appreciate your quality videos. In this instance, does the equation only hold if the angles are small, which was our assumption in the derivation. Thank you.
At 5:17 -- I understand that you used the small angle approximation assuming that both theta1 and theta2 would be equal along line segments bounded by delta x. My question is how exactly were you able to use the small angle approximation for ALL points along the string. Take for instance the points between any trough and peak, how would you be able to apply the approximation to those points where theta1 and theta2 would (at least by first glance) not be small enough to having sin (theta) = tan (theta)?
Since tension is unofirm and theta 1 equals theta 2 then sum of forces over Y equals zero not ma
elaborate explanation, thanks bro
why does lim as deltax ->0 of dS/dx imply that dS/dx=d/dx (dy/dx) 10:00
Energy is the ultimate integration of anything or anything else naturally universe ki efficiency hain maximum bot support dilva do stock market ka dividend detey rahana to sara desh aapko following karney lagega
11:01 “previous” i didn’t watch. now i’m lost. please don’t tell me to watch another video now. 😢😢😢😢
great explaination. Good job.
Why is delta(m) = mudelta(x)? Shouldn’t it be mudelta(s) which is the segment along the string? Or a we assuming since theta is small delta(s) and x are the same
why do we use theta1=theta1 in the horizontal direction but not in the vertical direction?
Будьласка допоможіть рівняння біжучої хвилі завдання на виведення з формули я нічого незнаю і не розумію.
Thanks so much, really appreciate it🙌
What's the purpose of the small angle approximation here? And why do we assume theta is a relatively small angle?
Thank you! You are a beast
Thankss
naah bro explained exponentially better than my proff. 😭
En büyük müsün bilmiyorum ama çok büyüksün ninja abi.
Very helpful thank youuu
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