Simplified ans--- (Infinity,-4] union [4, infinity)
Fun fact: f(x) represents the upper half of a hyperbola. To see this, note that the equation for a hyperbola has the standard form (x/a)^2 - (y/b)^2 = 1. In this case, a=b=4. Substituting this in and solving for y gives that y = +/- sqrt(x^2 - 16). To obtain a function of x (as this result is a relation but not a function), you simply choose either the positive or negative square root.
ok but why did we flipped sign for negative value ?
domain expansion
Domain is [-infinity,-4], [4,+infinity]
You are not finding the domain but rather the domain when the range is the real numbers
(-4,-infinity)u(+4,,+infinity)
but 4 is a working number , b/c when you square 4 and decrease 16 it gives you 0, and zero of square root is zero so it should be D=R / (-4,4)
There’s no problem mathematically to have a function over the imaginary numbers. In fact it is required in many engineering disciplines
Plz also solve for range ... Plz
How to you determine the inequalities signs? Like why x>4 not 4>x ?
A better solution would be taking whole x²-16 greater than or equal to zero then use wavy curve method to find the solution
So (-inf,-4]U[4,inf)
Of course I had to get it now after the test
Wouldn't it be better to say x²>16 |x|>4 x>4 or x<-4 I know there should be a "greater than or equal to" instead of "greater than" symbol but I don know how to write that.
Can you say |x|>=(greater than or equal to)4?
Silly questions 😁 for my class
Thnkuuuu
So is f of x 4 or -4
@4thsanninn