There is another easier way to get the answer of question 4: Divide through by 3 to reduce the equation 18x4 + 73x2 + 35 This way when you equate x2 = A it becomes: 18A2 + 73A + 35 Rather than using the formula method which seemed pretty much, you can factorize: 18A2 + 10A + 63A + 35 => 2A(9A + 5) +7(9A + 5) => (2A + 7)(9A +5)
Thank you for your video! Some of the questions in the video actually came out in the real exam yesterday! I hope I did well. Thank you so much for making this video!
Great work man, appreciate you hardwork. Please continue this series!!!
I think you can compare the numbers in the question no 2 like: when you rearrange the first eqn y=7x/9 - 13/3 then just plug the value of the constant for eg in the first option 0 (3r+"0") then check for the same in y coordinate and you can see -13/3
in the 3 question you could find the zeros just by the original form and made it equal to 154
for question two if you want to do less math you could just plug in the x and solve for the y, and if it matches up with the y in the solution you would have found your answer
In the first question, how do we know what is x? For example, when we're looking at x>k or x<j I know where j and k are, but where or what is x?
Very helpful, thanks! Amazing job.
for the triangle question how did you find the adjacent and hypotonuse especially since it isnt really clear for the entire triangle ABC. Also thanks Drew for the walkthrough for the questions <3
For question 4, we have an another simple way to do: AB^2 = BC.BD => (AB/BD)^2 = BC/BD <=> 363/BD^2 = 132/BD Just give BD = x and we can solve the problem.
Hey Drew, how are you? For the last question how can you assume the factors of the quadratic function both ax^2+b and the other one isn’t (cx^2+d)?
btw these questions are from preppros 150 hardest dsat questions book i think you should mention him just in case
Hi! for the last one, why are both factors ax^2 +b? because one of the other ones is cx^2+d. Is it because of the uncertainty of how we should order the factors? This was very useful btw, I gave myself a pat on the back when I knew I could solve the first three correctly without any problems, your idea with using theta for the circle problem actually gave me a lot less confusion from the way I'd normally solve it (by marking which sides looked equal lmao) thank you!
I am a greek 10th grader and most people in my class would be able to solve these problems
So useful, thabk you so much!!
Currently, I am preparing for the SAT exam and practicing math test papers since Math is my strength and I intend to strengthen it even further. I recently attempted solving questions from the blog '20 Hardest SAT Math Questions Ever' by Moonpreneur and failed to solve questions no. 2, 9, 12, 15, 16, and 20. I want to see if somebody would like to have a look at these questions and tell me how to tackle them.
hi drew, studying for the sat and stumbled across your vid. it's been helpful but i wanted clarification on for the first question: how do you know x>k is wrong if you dont know k is?
You didn’t have to use the quadratic formula for the last question. What I did was find the gcf for the original problem and then factored it by doing c times an and finding factors that multiplied into ac that equaled to b when added. So I ended up with the same equation: 3(2x*2+7)(9x*2+5). I think this could be easier when solving. I also have a question though. I did get this one right but I wanted to know how (9x*2+5) also = ax*2 +b? I thought (2x*2+7) was equal to ax*2 +b. So isn’t 9x*2+5 supposed to = cx*2+d?
Hey bro, for number 3 the problem is a bit wrong. The product of solutions is 22, not 154.
@RisetotheEquation