Yes I wanna see the Schrodinger's process
Yes, show us the original derivation. Thanks.
This is really good. Spent months pondering many derivations of SE. This looks the best. Will read that paper with interest.
Yes, it would be incredible to see how Schrödinguer derived it. It doesn't matter if the video is 1 hour long👀
You missed out the potential term in the explanation. Schrodinger also "derived" a hyperbolic version of the equation but dropped it as it didn't predict good results of something which is why he dropped it. I'd be interested in seeing a video on that.
Thanks for this simpler intro. And Yes Yes Yes to Schrödinger's one Pleaaaaase :) Simply drooling over your own usual incredibly talented coverage of complex matters into layman terms.
Yes! I want to see Schrödinger's way of approaching his equation.
Tak!
Beautiful derivation. ❤thank you very much.
5:30 Another reason for not taking the square root is that momentum is actually a vector, so if you want to take the square root, you have to write the length of the vector p instead of only p. When using the squared form, it's enough to simply write the square of the vector p, no absolute value needed.
Another great video from you that has made it to the top of my favourites list. Yes please do the other derivation too.
Brilliant content. Thank you for sharing your knowledge with us 🙌
Please also make a video about Schrödinger's derivation Also I love your videos, don't stop making them
Please make a separate video how Schrodinger derived his equation
How come you get plank constant on both sides of the equation? Could we not simplify removing one h on both sides? Actually I’m used to see momentum squared where it says h squared.
Would be fantastic to see a video with Schrödingers specific derivation. Amazing content as always!
Of course, we'd love to see the separate video. This may just help make the other graspable, but even so... :P
I'm very impressed with this video. Simple logical steps that get us to Klein-Gordon. Details worked out by the student.
Do thisr equation work for relativistic particles? I would suppose not at least with this derivation.
@iamharsh23