@strategic_nexus
Level 1 : 2 Level 2 : 42 Level 3 : 7 Level 4 : 17/30 Level 5 : 6.9 Level 6 : 11.34 Level 7 : 20 1:24 Level 8: No 1:33 Level 9 : x=7 1:46 level 10 perimeter= 22 and are of circle = 25π≈78.57 1:43 Level 11 62.5 dollars 2:16 Level 12: 81 2:27 level 13: 0.5 Level 14 : (x,y)=(7,5) Level 15: 3 Level 16 : (x-4)(x+3)=0 Either x=4 or -3 Level 17 : 1 Level 18 : 0.75 = ¾ Level 19 : x=⅔Log(3) with base 2 Or x= ln9/ln8 there are various ways to write it Level 20 : 10th term = 39 Summation of first 10 terms = 210 Level 21 : -30 Level 22 : -x²sinx+2xcosx Level 23 : 8/3 unit sq Level 24 : 70 Level 25 : The rest will come later Someone please like this comment so that I can come back to solve these left
@Atistatic
The fun part is that the level 50 isn't even the deepest part of math, is just a beginning of the rabbit hole.
@bosorot
Congratz after 50 levels , you can get a job at Starbucks.
@sanjithmuralidharan6425
Level 1 : 2
Level 2 : 42
Level 3 : 7
Level 4 : 17/30
Level 5 : 6.9
Level 6 : 11.34
Level 7 : 20
Level 8 : No
Level 9 : x=7
Level 10 : Perimeter = 22 units, Area of circle = 25π square units, which is approxiametely 78.5398163397
Level 11 : $62.5
Level 12: 81
Level 13: 1/2 = 0.5
Level 14: (x,y)=(7,5)
Level 15 : 3
Level 16 : (x-4)(x+3)=0, hence x = 4 or x = -3
Level 17 : 1 + 1/2 = 3/2 = 1.5
Level 18 : 3/4 = 0.75
Level 19 : x = (2Log(3))/3 with base 2 or x = Log9 with base 8 or x = Ln9/Ln8 where Ln(e)=1
Level 20 : 10th term = 39, Summation of first 10 terms = 210
Level 21 : [ 6 -3 ] (These are not 2 different matrices; they are a single 2×2 matrix.)
[ 12 -9 ]
Level 22 : -x²sinx + 2xcosx
Level 23 : 8/3 square units
Level 24 : 70
Level 25 : Tanx = (1 + √ 2)/2 or Tanx = (1 - √ 2)/2
Level 26 : 7/10
Level 27 : Focus = (0,2), Equation of directrix is y = -2
Level 28 : 7C3 = 140 ways
Level 29 : 1/48
Level 30 : Second derivative is -1/x^2 + 6/x^4, minimum value of y is Ln(√2) + 1/2, which is achieved at x = √2
Level 31 : [ -24 18 4 ]
[ -26 2 16 ] the whole matrix divided by 70, which is the determinant of the original matrix.
[ 43 -6 -13 ]
Level 32 : x = +2e^(iπ/4), -2e^(iπ/4), +2e^(i3π/4), -2e^(i3π/4)
Level 33 : sinx = x - x^3/3! + x^5/5! - x^7/7! ....., where 3!=6, 5!=120, and 7!=5040
Level 34 : 3i - 21j + 15k
Until level 34 is what is taught in high school, at least in India, I don't know about other countries
@euyn_009
The disrespect in the thumbnail is unmeasurable.
@davethesid8960
These levels aren't necessarily building on each other. So one can be at multiple levels at the same time.
@Luka_D_Snots
As a uni student most of the levels past 21 are in wrong order but otherwise it is a great intuitive video for those teenagers interested in mathematics
@dustinbachstein3729
Level 51 combines number theory with complex analysis. The question is simple: Prove or disprove the Riemann hypothesis.
@OhNoNotAgain42
I have 2 engineering degrees and have been a licensed engineer for 30 years. We learned up to Level 40 at university. Never used higher than Level 13 since graduating
@SwastikUpadhyay-b3j
tbh a good jee(exam for getting into a college of engeneering in India) aspirant can easily do 25-30 of these questions.
@EulerD
An important step is understanding the question.
@loverdraw4247
All answer: Level 1: 1+1= 2 Level 2: 7*6=42 Level 3: 56/8=7 Level 4: 7/6-3/5=(50+(20/3))/100≈0.5667 Level 5: 4.2+2.7=6.9 Level 6: 4.2*2.7= 11.34 Level 7: 25% of 80 equals 20 Level 8: no, 253 isn't divisible by 3 because 2+5+3=10 and 10 is not a multiple of 3 Level 9: 1- x+5=12 2- 12-5=x 3- 12-5=7 x=7 Level 10: 1-the formula to get the perimeter of a rectangle is 2*L + 2*l with L=7cm and l=4cm: 2- 2L+2l= Perimeter 3- 2*7+2*4= Perimeter 4- 2*7+2*4=22 Perimeter = 22cm Level 10.5: 1-to calculate the area of a circle the formula is πr². while knowing that the radius is half the diameter and that the diameter is 10cm: r=d/2=10/2=5 so the radius is 5cm. 2- πr²= Area 3- 5²π= Area 4- 25π= Area 5- 25π≈ 78.54 Area ≈ 78.54cm² Level 11: 1-since I have a 20% discount, $50 was 80% of the initial price. 2-to find the initial value you need to know the value of 1% so we do 50/80=$0.625, then we multiply it by one hundred: 0.625*100=$62,5. Level 12: 3^4=3*3*3*3=9*3*3=9*9=81 Level 13: to know the chance of having an even number, is the number of positions where the die is even on the total number, which makes 3/6 or 1/2. There is therefore 1/2 of having an even number. * the explanations will be simplified * Level 14: 1- x+y=12 2- 12-y=x; x= (12-y) 3- 3(12-y)- 2y =11 4- 36 - 3y - 2y = 11 5- (-5y) = -25 6- y=5 7- x = 12-5; x =7 x=7; y=5 the rest will come later :)
@prithvirajpatil3796
The video was great, helped me refresh all my basics . Need to watch more of this once in a while
@titanpie
Permutation and Combination is one of my favourite topics in maths and I find probability and Complex numbers to be Hardest topics for me
@javiersangon6769
Level 46 proof (Topology): To prove that [0,1] is compact in R with the usual topology, we are going to use the Heinel-Borel Theorem, which says that a set in R^n is compact if and only if it is closed and bounded. -Bounded: [0,1] is obviously bounded in R -Closed: To prove [0,1] is closed, lets going to see that R \ [0,1] is open with the usual topology (remember that the opens in R with that topology are the open intervals) R \ [0,1] = (-inf, 0) U (1, +inf) = U (a in R) ((-a,0) U (1, a)). Then, since we could write R \ [0,1] as arbitraty unions of opens, then that means it is open. Then, its complementary, [0,1], is closed. Then, since [0,1] is closed and bounded, using the Heinel-Borel theorem, we conclud that it is compact -Now, lets see that (0,1) is not compact. Since R with the usual topology is connected, then there’s no set opened and closed at the same time (excluding R and empty). Then, since (0,1) is not R or is empty, and it is opened, then it is not closed. Using again the theorem of Heinel-Borel, we can conclud that (0,1) is not compact
@firozkhan_2002
As a BTech student in Mechanical engineering from India, we have studied upto level 45 excluding Abstract math, functional analysis and Group Theory.
@carywalker7662
It's refreshing to see the honesty here. Thought I'd see everybody say, "50, easily." I recognized just about every topic, but my topology is weak. Honestly, I couldn't keep up with the ones I thought I could answer, but pretty sure I made it to the top half of questions. Maybe even past 30.
@AnimeArtist44
As an Indian I survived till level 40😅. Even before graduate
@NoobMan829
I'm at about level 45 as a EE graduate. Level 21 - level 34 is overvalued IMO cuz it's just nearly high school degree in Asia.
@brain_station_videos