@shortbusrob4073
For the first question im a little confused. Why would you want to bet your entire pot size when you're wrong half the time? Imagine you did the strategy and somehow got 99 flips correct in a row. Then on the last flip you are incorrect and because you bet your entire pot you're back down to zero. My first thought optimizing bet size was to use the Kelly Criterion where you take into account for the % win rate. The outcome from that was to bet 25% of your pot size every time.
@abhinabgogoi9134
Thabk you guys for making me feel how dumb i was born and how i dumb i will always be. Will stick to price action because i aint getting yours brains. Always Respect for your hardwork
@undeafetable9994
The last question in the video is solved in a very convoluted way when it can be done in one simple equation. The game is symmetic so if we don't immediately get the sequence the probabilities are mirrored. P(O) = p(s) + (1 - p(s)) * P(E) where: probability of success p(s) = (1/6)^3 As said in the video P(E) is just 1 - P(O) (this is trivial because P(O) + P(E) = 1) so now we can solve this equation: P(O) = p(s) + (1 - p(s)) * (1-P(O) P(O) + (1-p(s)) * P(O) = p(s) + 1 - p(s) (2-p(s)) * P(O) = 1 P(O) = 1/(2-p(s)) This is exactly 216/431 as mentioned in the video
@AB-uc5vj
you mean to tell me they use the same interview as the ones they did for my gambling job.... i should be a quant instead
@liminfer8380
why did you repost this video
@dmytrom.3010
is voice fry present at every Jane Street interview or just this video?
@HS-ce8vc
what is the answer of the second question? I got 216/431? not sure whether that's right
@CarbonTaxLOL
You don't need to know any of this to be a quant trader. You only need to know this to get a job. The rest of it is just buying the magnificent 7 and bitcoin.
@BreezeTalk
I am not confused, I am BreezeTalk.
@Corpsecreate
I think I dont understand the second question. If you want to know the probability that the number of rolls you did at the end of a 3,4,5 sequence is odd, isn't it 100%? You've rolled once, then twice, then three times...and 3 is odd. alternatively, if you're supposed to count the number of rolls from the very beginning (not just from the first occurrence of a 3), then there's a 50% chance that you began the 3,4,5 sequence on an odd number of rolls, which would change the answer to 50%. What am I missing?
@jayo1499
not only do you repost the video (without credit), but you claim its from jane street, when its not lmao
@spirit6221
Use the Kelly criterion
@tygo9967
I guess you guys don't teach risk management. The survival probability of this strategy is (1/2)^100
@jo-mang
You's guys is smart. I'm slow but I want to get it. Your formula is Just too fast to follow bruv. You's either in flow or this is staged. No canned laughter audio tracks, so maybe just a very Dry comedy sketch...? Which is it? Ps. Interviewer seems a bit waaay too overdramatic, but anyways... ha Be cool to screenshot the equation, like animated numbers on a blackboard/whiteboard or something? Maybe ya'll just need to hire a proper tech crew w/ all that baller dollar??? Know what I mean... yo Idk What would you like to do?
@Miketea_333
ok I just feel super dumb.
@Anonim29122