@-_IT_-

I would multiplied c by the quantity a+b to get the total area of the two rectangles.

@laurencolman9853

Thank you so much for your clear solutions of math problems. I am a 76 year old retired physician, cancer doctor, who needs to exercise his brain as well as his body to stay healthy. I find your problems fun and interesting to try to solve prior to peeking at your solution. By the way, my wife and I along with our first son and two dogs lived for three years in rural Pfalz and your videos bring back wonderful memories of experiences there and life-long friendships made while there.

@PresidentChristopher

For #5 I got C (a+b)

@HolySoliDeoGloria

#7 is ambiguous in several ways. I interpreted it to mean that the container, as depicted, shows the present status of the container, which AFTER balls had been taken out (by blind draw). The balls that were taken out gave the result that 2/3 were white and 1/3 were red, but the question doesn't tell us anything about either how many total balls were in the container before the experiment began or how many balls were withdrawn during the experiment. So the possible solutions are to add any combination of red and white balls in a 1:2 ratio, while leaving the 4 white balls. I don't think that this was what was intended.

@johnnyragadoo2414

The rectangle problem illustrates distribution nicely. You can see that ac+bc is the same region as c(a+b).

@gbenother8755

Hello my Lovely! You are so refreshing! I am an old guy, former technical writer, and I've always loved math. Your tutelage is just terrific, and to have it served up by such a beauty, well, I subscribed the moment I found you. Now and again, though, I see the difference in math teaching over the years. For example, In Number 4 , when I was in school, we were not to leave an improper fraction as a final answer. We had to change 7/5  into 1 2/5 to get full credit. Sometimes we had to give the answer as 1.4. Please keep doing what you do so well. I always look forward to your videos.

@tonisee2

Trivial. 30 years since finishing highschool... ;-)
Actually, I'd disagree with the problem where one had to find expression for angle alpha. In the solution here, expression was found for sin(alpha) ...

@davidsasson3969

תודה!

@davepowder4020

Starting a week with Math Queen Susanne!  Your videos are very much worth watching several times in order to get the lessons down well.  🤓

@timor64

10:55 - the trignonimc expression to give you alpha is the Inverse sine of r/t

@donsharpe5786

It is fun watching you solve maths problems.  The one I couldn't do was the sin wave, because I didn't know how.

@3dplanet100

No.2
I did it backwards.🙂 What I did was that 60cm I moved the decimal point two places to the left, which is .6cm. 
0.06<0.6

@retread1083

1 - Vertical angles are equal.  Very kind of the creator of this test to start with something easy.  Boosts the confidence of the student taking the test.
2 - Slightly more work than the first problem but still fairly easy.
3 - I'm lazy.  After counting the shaded segments, I would have started the denominator count at three and counted the unshaded segments.
4 - Another easy one.  Just plug in the values and perform the operations.
5 - I would have combined the partial sides first, then performed the multiplication.  That's just how my mind works.  A = c(a+b)
6 - We're crossing over into more work.  Moderately simple process but there are several steps to perform.
7 - 10th grade for me was 1970.  I don't recall seeing anything like that tree diagram.  I'm guessing there isn't a definitive answer for the total number of balls at the onset?  Just the requirement that the ratio of white to red matches the probability?  Could there have been 6 white balls and 3 red balls at the onset?
8 - Easy enough if you remember the definition of at least one trig function.
9 - I would have crashed and burned on this one.  I don't remember how to find the amplitude, period, phase shift, and vertical shift of any of the trig functions.
10 - Conversion to and from scientific notation is a simple but important skill.

@sthenzel

I think, problem 7 should yield a different answer:
The tree diagram was drawn DURING the experiment of taking out balls, it neither shows the contents of the container prior to the experiment, nor after the experiment, as there are still balls left (the taking-out has not yet finished).
So to get out the necessary minimum number of balls for the tree diagram, there had to be at least two red balls and one ADDITIONAL white ball in the container. 

Why not more red balls?
We do not know how mixed the balls are, so it is at least possible, that even with a container containing five white and just two red balls, to pull out only one white but all of the two red balls.
And why that?
Neither container nor balls have a memory or influence of what color was already removed, so only the result at the very end of the experiment will give the red/white ratio in the container.

@neville1353

Thant you so much for you maths quizzes they are brilliant I wish you were my maths teacher when I was at college

@terencemeikle534

In no.5, a simplification could give c(a+b). Or is this above the requirement for 10th grade?

@johnnyadams3244

Really enjoying your videos. When I taught fractions to my fourth and fifth grade students, I used the word ‘simplified’ because the word ‘reduced’ was a bit confusing.

@damonf6564

I did Question 4 in my head and noticed I did something different from how she did it. I worked out the top before I even started the bottom. It is less that I need to hold in my head at one time and the single number is easier to remember than the whole equation is. Explaining it in the order that you would use to mentally calculate the answer would be useful to those who don't yet know how to do that.

@toddshook1765

I sometimes will pause the video and figure on my own to see if I get correct. Mostly incorrect but as I try with your videos getting better. 
Thanks for these post. Working my thinking skills.

@DarkoMarković-r5c

Fantastic.
Best regards from Belgrade Serbia 🇷🇸♥️👍🙋