3362. Zero Array Transformation III | Leetcode Daily - Python

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Dive into a challenging LeetCode problem, 'Maximum Query Removals'! We're given a list of numbers (nums) representing operation demands at each index, and a set of queries, each defined by a start and end range. Our goal is to satisfy all demands using the minimum number of queries and then determine how many queries were unused. This video breaks down an efficient greedy approach: we process nums index by index, maintaining a count of currently active operations using a difference array. When more operations are needed, we greedily select from available queries, prioritizing those with the largest right endpoint using a max-priority queue. We'll walk through the Python solution step-by-step, including the logic for handling query availability, selection, and tracking operation counts. Finally, we'll analyze the time and space complexity (O(N + M log M) time, O(N + M) space) of this optimal strategy. Learn how to tackle similar problems involving intervals and resource allocation!

Perfect for coding interview preparation and improving problem-solving skills.

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Solution Link:
leetcode.com/problems/zero-array-transformation-ii…

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